whats the formula for an area of a triangle. the formula must be for a triangle thats not right nor isocellies.... its for a trig question so it might include a sinx in the formula.
2007-11-19 12:41:40 · 9 answers · asked by john doe 2 in Science & Mathematics ➔ Mathematics
Area of triangle = 0.5 * a * b * (sin C)
where a and b are any two adjacent sides and angle C is the angle enclosed by sides a and b.
This formula works for all triangles.
2007-11-19 12:47:42 · answer #1 · answered by somerandomguy 2 · 3⤊ 0⤋
The formula for the area of a triangle is one half the length of the base times the height. This works for all triangles. Of course, for a triangle that isn't a right or isoceles, you wll probably have to use trig to find the height. Without knowing which measurements of the triangle are given, I can't help any further.
2007-11-19 20:50:10 · answer #2 · answered by Demiurge42 7 · 0⤊ 0⤋
Hey there!
Depends.
The standard form for area of a triangle is Area=1/2*base*height.
When you said sin(x) in the formula, I assume you meant the area of an SAS triangle i.e. sides a and b, with included angle C.
Here's the area of a triangle.
A=1/2*a*b*sin(C).
Take a look at this. If you substitute 90 for C, we get:
A=1/2*a*b*sin(90) -->
A=1/2*a*b*1 -->
A=1/2*a*b
Hence, the original formula for the area of the triangle!
Hope it helps!
2007-11-19 20:48:37 · answer #3 · answered by ? 6 · 1⤊ 0⤋
A= 1/2bh
Which in words is half times base times the height
base is horizontal line and the height is the line that goes up and down the center of the triangle
2007-11-19 20:47:01 · answer #4 · answered by hunny d 1 · 0⤊ 0⤋
area for right angle trigangle is base x height x 1/2
for isocellies is 2 x ( base x height x 1/2 )
and for the other triangles are the same, simply cut them into another right angle triangle, and then you will be able to calculate the area.
2007-11-19 20:48:52 · answer #5 · answered by lundul 2 · 0⤊ 0⤋
Area Triangle = (base * height) / 2
2007-11-19 20:46:00 · answer #6 · answered by randy3soccer 1 · 1⤊ 1⤋
Let ABC is a triangle. Draw AD perpendicular from A to BC.
Now in triangle ADB
AD = h
AB = hypotenuse
Sin(B) = AD/AB = h/AB
h = AB* sin(B)
area of triangle = bh/2 = BC(AB*sin(B)/2 = ac sin(B)/2
similarly you can prove that A = ab Sin(C)/2 or
A = bc Sin(A)/2
2007-11-19 20:53:39 · answer #7 · answered by mohanrao d 7 · 0⤊ 0⤋
Many methods:
http://en.wikipedia.org/wiki/Area_of_triangle#Computing_the_area__of_a_triangle
2007-11-19 20:51:51 · answer #8 · answered by Nigel M 6 · 0⤊ 0⤋
if you give me the entire question I will help you figure it out
2007-11-19 20:45:07 · answer #9 · answered by ? 2 · 0⤊ 3⤋