What is the component of the weight force parallel to the plane's surface?

Question

A 215-N box is placed on an inclined plane that makes a 35.0 degree angle with the horizontal.

Answer 1

The weight force is 215 N pointed down. You probably know the force parallel to the surface is either
215 N*sin 35 or 215 N*cos35

If the incline is temporarily set to zero degrees, the force parallel to the surface is zero. I hope you see that. Which trig function is compatible with that?

Answer 2

expensive Jessicat, once you have those variety of questions, evaluate if the theta with horizontal or vertical? It would desire to be with horizontal !! If it suggested that's with vertical, replace it !! HOW?? Use ( ninety - the given theta, that's with vertical) in this it says with horizontal. once you stumble on factors of a tension, you in basic terms use (the tension * cos theta) that's the ingredient parallel to the airplane's floor, or (the tension * sin theta) that's perpendicular to the airplane's floor. (this replaced into on your help) And right here is your question ! use (215 * cos 35.0) = practically 176 N