2007-11-19 11:25:02 · 9 answers · asked by ahmed 1 in Science & Mathematics ➔ Mathematics
[02]
2x^2+3x-3-(3x^2+5x-7)
=2x^2+3x-3+3x^2-5x+7
=5x^2-2x+4
2007-11-19 11:30:13 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
Translate to math:
2x^2 + 3x - 3 - [-3x^2 + 5x - 7]
= 2x^2 + 3x - 3 + 3x^2 - 5x + 7
= 5x^2 - 2x + 4
2007-11-19 19:28:12 · answer #2 · answered by piggy30 3 · 0⤊ 0⤋
(2x² + 3x - 3) - (-3x² + 5x - 7)
= 2x² + 3x - 3 + 3x² - 5x + 7
= 5x² - 2x + 4
2007-11-19 19:29:14 · answer #3 · answered by gudspeling 7 · 0⤊ 0⤋
-5x^2+2x-4 the guy that said -10 is wrong
2007-11-19 19:28:58 · answer #4 · answered by cris 2 · 0⤊ 0⤋
subtract like figures
-5x^2+2x-4
2007-11-19 19:27:57 · answer #5 · answered by Dave aka Spider Monkey 7 · 0⤊ 1⤋
simple
5x^2-2x+4
2007-11-19 19:28:47 · answer #6 · answered by NotForSale 1 · 0⤊ 0⤋
equals -5x^2+2x-4
2007-11-19 19:27:06 · answer #7 · answered by ひいらぎ 5 · 1⤊ 1⤋
  (2x² + 3x - 3)
-(-3x² + 5x - 7)
----------------
   5x² - 2x + 4
2007-11-19 19:30:28 · answer #8 · answered by DWRead 7 · 0⤊ 0⤋
5x^-2x+5
2007-11-19 19:27:31 · answer #9 · answered by me 4 · 0⤊ 3⤋