2007-11-19 11:16:05 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(x+4) - (-x-3) DISTRIBUTE the - into the parenthesis
x + 4 + x + 3
2x + 7 ANSWER
2007-11-19 11:19:38 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Distribute first
1x+4(1)+-(1)(-x)+(-1)(-3)
x+4+x+3
Add like terms
(x+x)+(4+3)
2x+7
Hope I helped
2007-11-19 19:22:05 · answer #2 · answered by Bre M 2 · 0⤊ 0⤋
(x+4) - (-x-3)
what u do here is cha ching or convert the negative to positive. quiet simple. its like multiplying everything in the right quatations by a -1.
x+4 -1 x -X -1 x -3
(x+4)+(x+3)
2x + 7=0
-7 -7
2x=-7
/2 /2
x= - 7/2
2007-11-19 19:24:02 · answer #3 · answered by pacmanjones42 2 · 0⤊ 0⤋
Distribute first
x+4+x+3
Answer=2x+7
or
x+4+x+3=0
2x+7=0
2x= -7
x= -7/2
2007-11-19 19:30:31 · answer #4 · answered by niravlim 1 · 0⤊ 0⤋
(x + 4) - (-x - 3)
Use foil to distribute the - [remember negative of a negative is positive so -(-x)=x]
= (x + 4) + x + 3
Add
= 2x + 7
2007-11-19 19:19:32 · answer #5 · answered by McDudette 3 · 0⤊ 0⤋
x+4-(-x-3)
x+4+x+3=2x+7
2007-11-19 19:32:35 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
(x+4) - (-x-3)
ok first distribute the negative then rewrite the problem without the parenthesis
x+4 + x+3
now combine like terms
2x+7
there you go!
2007-11-19 19:20:05 · answer #7 · answered by justme 3 · 0⤊ 0⤋