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by substitution method x^2=t and "integratioan byparts" integration is going to infinite.........

2007-11-19 10:03:40 · 1 answers · asked by dasari_biet 1 in Science & Mathematics Mathematics

1 answers

The integral cannot be evaluated in closed form. I don't see the value in the substitution
t = x². You will end up with

½ ∫ (√t)e^t dt

which is no more tractable than the original form.

Integration by parts of the original:

dv = x e^(x²), u = x
v = ½ e^(x²), du = dx

∫ x² e^(x²) dx = ½ x e^(x²) - ½ ∫ e^(x²) dx

and there is nothing more to be done with the remaining integral.

2007-11-19 10:50:52 · answer #1 · answered by Ron W 7 · 2 0

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