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I really suck at physics, can someone help me?

You ski down a frictionless icy hill that has a slope of 30 degrees above horizontal. What is the magnitude of your acccceleration down hill?

Can someone please explain?

2007-11-19 09:00:08 · 1 answers · asked by The Problem Solver 3 in Science & Mathematics Physics

1 answers

The force that propels the skier down the hill is Fd
Fd=mgsin(30) where
m - the mass of the skier
g - acceleration due to gravity

Si since Fd=ma=mgsin(30)
the acceleration you seek is
a=g sin(30)
a=9.81(.5)=4.91m/s^2

2007-11-19 09:10:47 · answer #1 · answered by Edward 7 · 0 0

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