If you are taken to the emergency room in IL and you do not pay the fees (which are extremely high for simply lying in bed taking a urine test) can they put you in a collection agency? Is there a way to argue the fees without having to go to court and getting a lawyer?
2007-11-19 08:50:23 · 7 answers · asked by Peter P 1 in Politics & Government ➔ Law & Ethics
If you fail to pay, it will immediately go to a collection agency.
2007-11-19 08:54:15 · answer #1 · answered by CGIV76 7 · 1⤊ 0⤋
Yes they can put it to a collection agency. You can call the hospital and try to dispute the amount to see if they will lower it. Or you can make payment arrangements. You were in the emergency and did have the test done so the bill is yours to pay. It is not your call on how much they charge. I seriously doubt any lawyer would try to take this to court. It would end up costing you more than to just pay the bill you owe.
2007-11-19 11:02:25 · answer #2 · answered by mnwomen 7 · 0⤊ 0⤋
Sure they can. It is a billing for services rendered. You can argue the fees with the hospital Billing Department but don't expect much help.
2007-11-19 08:55:35 · answer #3 · answered by sensible_man 7 · 0⤊ 0⤋
Yes, than can send them over to collections unless you make payment arrangements with them. There have been many people with high bills that have had their debt written off by the hospital by state charity. You need to fill out a hospital form for this...
2007-11-19 08:54:25 · answer #4 · answered by Workcompguru31 4 · 0⤊ 0⤋
When you "signed" yourself into the emergency room you agreed to pay all the fees. Sorry but, your on the hook.
2007-11-19 08:58:20 · answer #5 · answered by Anonymous · 0⤊ 0⤋
If you cannot pay your bill you should hqave contacted the hospital indigent care office immediately to make arrangments -- otherwise you made the bill, you pay the bill.
2007-11-19 08:54:11 · answer #6 · answered by Susie D 6 · 1⤊ 0⤋
No, you received the service, and are responsible for the fees.
2007-11-19 08:53:51 · answer #7 · answered by Squat1 5 · 0⤊ 0⤋