Can you solve this physics energy/work question?

Question

Thanks for your help and make sure you show your work!

A mover slides a refrigerator weighing 650N at a constant velocity across the floor at a distance of 8.1m. The force of friction between the refrigerator and the floor is 230N.
a) How much work has been performed by the mover on the refrigerator?
b)If the work was done in 55 seconds, then what is the power of the mover?

Answer 1

There's information in this problem you don't need. Since the refrigerator is moved at a constant speed by a force of 230 N over a distance of 8.1 m, the work is simply force times distance. If the work is done over a certain time, the rate at which the work is done (that is, the power) is work divided by time.

Answer 2

Let the velocity of the block + bullet is v m/s, By the paintings power relation:- =>W(friction) = ?KE =>Ff x s = ?KE =>µk x (m1 + m2) x g x s = a million/two x (m1 + m2) x v^two =>zero.25 x nine.eight x nine.five = a million/two x v^two =>v = ?forty six.fifty five =>v = 6.eighty two m/s Let the muzzle velocity of the bullet used to be u m/s earlier than the collision, By the regulation of momentum conservation:- => m1u1 + m2u2 = (m1+m2)v =>25 x 10^-three x u + zero = (25 x 10^-three + a million.35) x 6.eighty two =>u = 375.10 m/s