If two dice were rolled, and the two numbers were added, what would be the most likely result?

Answer 1

7

6/1
5/2
4/3
think of the game craps

Answer 2

OK you have 36 combinations

1-1, 1-2, 1-3, 1-4, 1-5, 1-6
2-1, 2-2, 2-3, 2-4, 2-5, 2-6
3-1, 3-2, 3-3, 3-4, 3-5, 3-6
4-1, 4-2, 4-3, 4-4, 4-5, 4-6
5-1, 5-2, 5-3, 5-4, 5-5, 5-6
6-1, 6-2, 6-3, 6-4, 6-5, 6-6

OK - looking at those 36 possibilities the following results come up when you roll the dice:

2 - 1 ; 1/36 = 2.78%
3 - 2 ; 2/36 = 5.56%
4 - 3 ; 3/36 = 8.33%
5 - 4 ; 4/36 = 11.11%
6 - 5 ; 5/36 = 13.89%
7 - 6 ; 6/36 = 16.67%
8 - 5 ; 5/36 = 13.89%
9 - 4 ; 4/36 = 11.11%
10- 3 ; 3/36 = 8.33%
11 - 2 ; 2/36 = 5.56%
12 - 1 ;1/36 = 2.78%

So for a total of 36 rolls, the most likely result, is a 7, about 17% of the time.

Hope that helps.

Answer 3

The possible outcomes are listed below:
1+1 = 2
1+2 = 3
1+3 = 4
1+4 = 5
1+5 = 6
1+6 = 7 *
2+1 = 3
2+2 = 4
2+3 = 5
2+4 = 6
2+5 = 7 *
2+6 = 8
3+1 = 4
3+2 = 5
3+3 = 6
3+4 = 7 *
3+5 = 8
3+6 = 9
4+1 = 5
4+2 = 6
4+3 = 7 *
4+4 = 8
4+5 = 9
4+6 = 10
5+1 = 6
5+2 = 7 *
5+3 = 8
5+4 = 9
5+5 = 10
5+6 = 11
6+1 = 7 *
6+2 = 8
6+3 = 9
6+4 = 10
6+5 = 11
6+6 = 12

Now you can figure the probability of the sum. As you can see, the most frequent sum is 7 which happens 6/36 or 1/6 of the time.

In graph form:
2 = (1,1) = 1/36
3 = (1,2; 2,1) = 2/36 = 1/18
4 = (1,3; 2,2; 3,1) = 3/36 = 1/12
5 = (1,4; 2,3; 3,2; 4,1) = 4/36 = 1/9
6 = (1,5; 2,4; 3,3; 4,2; 5,1) = 5/36
7 = (1,6; 2,5; 3,4; 4,3; 5,2; 6,1) = 6/36 = 1/6 <--
8 = (2,6; 3,5; 4,4; 5,3; 6,2) = 5/36
9 = (3,6; 4,5; 5,4; 6,3) = 4/36 = 1/9
10 = (4,6; 5,5; 6,4) = 3/36 = 1/12
11 = (5,6; 6;5) = 2/36 = 1/18
12 = (6,6) = 1/36

Answer 4

For 6 sided die? It would be 7. No other number within the range of 2-12 is capable of being added up to with all possible faces of the die.

Here are all of the combinations.
1+1=2
1+2=3
1+3=4
1+4=5
1+5=6
1+6=7
2+1=3
2+2=4
2+3=5
2+4=6
2+5=7
2+6=8
3+1=4
3+2=5
3+3=6
3+4=7
3+5=8
3+6=9
4+1=5
4+2=6
4+3=7
4+4=8
4+5=9
4+6=10
5+1=6
5+2=7
5+3=8
5+4=9
5+5=10
5+6=11
6+1=7
6+2=8
6+3=9
6+4=10
6+5=11
6+6=12

2 comes up 1 time
3 comes up 2 times
4 comes up 3 times
5 comes up 4 times
6 comes up 5 times
7 comes up 6 times
8 comes up 5 times
9 comes up 4 times
10 comes up 3 times
11 comes up 2 times
12 comes up 1 time

7 comes up more often than any other number. It is not that great of odds of coming up though. The seven has a 1 in 6 chance of being thrown. That is roughly a 17% chance.


Kudos to Puzzling. He beat me to the draw on this one.

Answer 5

7

Answer 6

7

Answer 7

the total of 7 has a 1 in 6 chance of being rolled - that's the highest 6 & 8 are a 5 in 36 chance each, 5 & 9 are a 4 in 36 chance each, 4&10 - 3/36, 3&11 - 2/36 and 2 or 12 - 1/36 each

Answer 8

6 or 7

Answer 9

2: 1, 1
3: 1, 2; 2, 1
4: 1, 3; 2, 2; 3, 1
5: 1, 4; 2, 3; 3, 2; 4, 1
6: 1, 5; 2, 4; 3, 3; 4, 2; 5, 1
7: 1, 6; 2, 5; 3, 4; 4, 3; 5, 2; 6, 1
8: 2, 6; 3, 5; 4, 4; 5, 3; 6, 2
9: 3, 6; 4, 5; 5, 4; 6, 3
10: 4, 6; 5, 5; 6, 4
11: 5, 6; 6, 5
12: 6, 6

7 is the most probable because the highest number, 6, and the loest number, 1, add up to 7. Therefore, it has the most possible combinations.

Answer 10

7,

think of it this way, you roll the first die, and no matter what number it shows, there is one number that could show up on the second die that would bring the total to 7. therefore one out of every 6 times the total will be 7.

Answer 11

7, if you mean the two numbers on the dice, rolled.