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CH3CH2Br + OH(-) ==>

CH3CH2Br + (CH3)CO(-)==>

Which [E2] reaction in each pair is faster?

This deals with stronger nucleophile, stronger base, the stronger the nucleophile, which favors the E2 eraction. But which base is stronger? I say it's the OH, but some have said it's the other one (CH3)CO-. So which base is stronger, and WHY? Please include his as part of your answer. Thank you.

2007-11-19 06:00:00 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

I think you mean (CH3)3CO-, which is tert-butoxide and a stronger base than OH because of the electron-donating character of methyl groups. So the second E2 is faster.

2007-11-19 06:05:09 · answer #1 · answered by steve_geo1 7 · 1 0

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