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Let a sequence be defined by x(n+1) = ( x(n)^5 +2)/6 with x(1)=0.

Show x(n+1)-x(n) =< 5/6 [x(n)-x(n-1)] =< 1/3 (5/6)^(n-1)

Presumably we can solve this using induction, though it seems quite tricky and I've made a mess of it so far. Or is there a better method? Thanks very much.

2007-11-19 05:53:00 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

This is fairly straightforward:
We have
x(n+1)=(x(n)^5 +2)/6 and
x(n)=(x(n-1)^5 +2)/6, so
x(n+1)-x(n)=(1/6)[x(n)^5 -x(n-1)^5].
Now factor x(n)^5-x(n-1)^5 and use the fact that x(n) is always between 0 and 1 (which can also be shown by induction).

2007-11-19 06:16:49 · answer #1 · answered by mathematician 7 · 0 0

See http://answers.yahoo.com/question/?qid=20071117155243AARKxCQ

2007-11-19 06:16:02 · answer #2 · answered by Ron W 7 · 0 0

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