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sin(-4π/3)= sin( (6π-4π)/3 )= sin(2π/3) =(√3) / 2
cos(-4π/3)= -cos( (6π-4π)/3 )= -cos(2π/3) = - 1/2
tan-4(-4π/3) = - √3

2007-11-19 03:34:14 · answer #1 · answered by mbdwy 5 · 0 0

-4pi/3 is the same as 2pi/3 to in the second quad

sin pi/3 = sqrt(3)/2 cos pi/3 = 1/2 and tan pi/3 = sqrt(2)/2

so sin(-4pi/3) = sqrt(3)/3
cos(-4pi/3)= -1/2
tan(-4pi/3)=- sqrt(2)/2

2007-11-19 03:30:49 · answer #2 · answered by norman 7 · 0 0

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