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hanging 2.00-kg block begins to accelerate a 4.74-kg block on a horizontal surface. But a rope connected to the wall at 31.5 degrees brings the block to an equilibrium position. The coefficient of friction between the surface and the 4.74-kg block is 0.130.



(a) What is the minimum tension (in Newtons) in the angled rope that maintains this equilibrium condition?
N

2007-11-19 02:55:35 · 1 answers · asked by ags101 2 in Science & Mathematics Physics

1 answers

Your diagram should look something like this:

http://s236.photobucket.com/albums/ff177/jsardi56/?action=view¤t=blockequilibrium.jpg

F(acc. small block) = F(friction) + F(resistive horz.)
F(tension) = F(resistive horz.)/sin31.5
F(tension) = [(2.00)(9.8) - (0.130)(4.74)(9.8)]/sin31.5
F(tension) = 25.95N

2007-11-20 23:54:31 · answer #1 · answered by jsardi56 7 · 0 0

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