algebra1 help!?

Question

im supposed to divide the problem below, but i cant figure out how to solve it.

(3x – 2)(x - 4) – (x - 4)(6 – 5x) / (4 – x)(8x – 1)

=[3x^2 -14x+8 -(-5x^2+26x-24)]/[(4-x)(8x-1)]

= [8x^2-40x+32]/[(4-x)(8x-1)]

= 8x^2 -5x +4)/[(4-x)(8x-1)]

=(8x-1)(x-4)/[(4-x)(8x-1)]

= -1

this was my teachers response, but i cant figure out how to factor out the GCF.
Don't FOIL in the numerator. Factor out the GCF instead. What do you get?

Answer 1

I assume you mean
( (3x – 2)(x - 4) – (x - 4)(6 – 5x) ) / (4 – x)(8x – 1)


Let's rip that (x-4) out of there, first. Fiddle the denominator:

((3x -2)(x-4) - (x-4)(6-5x)) / (x-4)(1-8x)

((3x-2) - (6-5x)) / (1-8x)

(8x-8) / (1-8x)

Answer 2

(1) x+(x+1)+(x+2)=9 3x + 3 = 9 3x = 6 x = 2 (2) (y-2)+(y-1)+y= -3 y - 2 + y - 1 + y = -3 3y - 3 = -3 3y = 0 y = 0 (3) 19n -11-12n - 5 = 5 7n - 16 = 5 7n = 16 + 5 7n = 21 n = 21/7 = 3 (4) 7h -17- 6 + 4h =17 11h -23 = 17 11h = 23 + 17 11h = 40 h = 40/11 (5) -2t+3(2+t) = -10 -2t + 6 + 3t = -10 t + 6 = -10 t = -16 (6) 2(x+3)-6x-4 = 8 2x + 6 -6x - 4 = 8 -4x + 2 = 8 -4x = 6 x = -6/4 = -3/2 (7) 4z+2(z+7)= -14 4z + 2z + 14 = -14 6z = -28 z = -28/6 = -14/3 (8) -5(1+w)+4w= 8 -5 - 5w + 4w = 8 -5 - w = 8 -13 = w (9) -3(2-y)+2y= 7 -6 + 3y + 2y = 7 -6 + 5y = 7 5y = 13 y = 13/5 (10) 5a-(1-a)+4 = 9 5a - 1 + a + 4 = 9 6a + 3 = 9 6a = 6 a = 1 (11) -7 - (-3 - 2g) - 10 =0 -7 + 3 + 2g - 10 = 0 -14 + 2g = 0 2g = 14 g = 7 (12) 1.5k - (k +2.4) = 17.4 Multiply by 10 on both sides 15k - 10(k + 2.4) = 174 15k - 10k - 24 = 174 5k = 174 + 24 5k = 198 k = 198/5 or 39.60 (13) 3s - (0.5s+7.2) = 32.8 Multiply by 10 on both sides 30s - 10(0.5s + 7.2) = 328 30s - 5s - 72 = 328 25s = 328 + 72 25s = 400 s = 400/25 = 16

Answer 3

factor out x-4 in the numerator
do you know that in the denominator you have 4-x
that is actually same as -(x-4) there fore (x-4)/-(x-4)=-1
you get [ (3x-2)-(6-5x)]all over -(8x-1)
the numerator becomes 8x-8
denominator is -(8x-1)
the answer is (8x-8)/(1-8x)

Answer 4

(8x^2-40x+32) / (4-x)(8x-1)
8(x^2-5x+4) / (4-x)(8x-1)
8(x-4)(x-1) / (4-x)(8x-1)
-8(4-x)(x-1)/(4-x)(8x-1)
(4-x) cancels out
8(1-x)/(4-x)(8x-1)
This is as far as you can go.