Alright easy one cause I'm dumb?

Question

I can't think this morning - all I need to do is solve for v^2

mgh=mg(3/4h)+1/2mv^2

little help =/


note: I got through hisghschool and through calc 1 in college.... and I can't do this problem hehehe.... sad really =/

ACTUALLY mr accuser... I don't nor ever will cheat...Thats not what I was hinting at... I can't remeber this basic stuff is that a problem? People are dumb..

Answer 1

well, m is in all terms, so you can divide that out immediately, leaving you with
gh=g(3/4h)+1/2v^2
gh-g(.75h)=1/2v^2
(g(h-.75h))2=(1/2v^2)2
v^2= 2g(.25h)
v^2= .5gh

there ya go. Just started doing his stuff in AP Physics =b

Answer 2

Assuming m, g, h, and v are all separate variables, we can simplify a little bit, but that's all.

first, divide everything by m

gh = 3/4gh+1/2v^2

Then subtract 3/4gh

gh/4 = 1/2v^2

Multiply both sides by 2

gh /2 = v^2

There you go

Answer 3

hehehe.... yes it is really sad that you have cheated your way through high school and college. Do you really think that cheating will get you anywhere,but to a position where you can't function?

Answer 4

gh = 3gh/4 + v²/2
2gh - 3gh/2 = v²
(1/2)(gh) = v²

Answer 5

v = (√2·√(g·h))/2

or

v = -(√2·√(g·h))/2

or

m = 0