let say you have mgh-mg(3/4h) can you cancel m and g?
also, if you have mgh/(1/2)mv can you cancelout the m?
2007-11-19 01:52:10 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
>>let say you have mgh-mg(3/4h) can you cancel m and g?
No. You'd need to factor them out.
= mg(h - 3/4 h)
= mg(1/4 h)
>>also, if you have mgh/(1/2)mv can you cancelout the m?
Yes, in that case you can cancel out the m.
= gh / (1/2)v
2007-11-19 01:56:59 · answer #1 · answered by Mathematica 7 · 2⤊ 0⤋
to the first part not exactly, but you can do this
mg[h-(3/4h)], which is just collecting like terms on the outside
to the second, you sure can take out the m
gh/[(1/2)v]
2007-11-19 09:57:35 · answer #2 · answered by Mic K 4 · 0⤊ 0⤋
if mgh-mg(3/4h) = something then
(1/mg)*(mgh - mg(3/4h)) = (1/mg)*something
(4/4h) - (3/4h) = something/mg
h/4 = something/mg
This works because (1/mg)*mg = mg/mg = 1.00
Algebra states that anything can be preformed on one side of the equation if the same operation is preformed on the other side.
2007-11-19 10:02:52 · answer #3 · answered by Roger S 7 · 0⤊ 0⤋
(1/4) mgh is answer
2007-11-19 10:59:14 · answer #4 · answered by Como 7 · 0⤊ 1⤋
during subtraction you cant cancel
but during division you can
2007-11-19 09:56:17 · answer #5 · answered by Murtaza 6 · 0⤊ 0⤋