Need Help with This Physics Question????

Question

The parallel axis theorem provides a useful way to calculate the moment of inertia I about an arbitrary axis. The theorem states that I = Icm + Mh2, where Icm is the moment of inertia of the object relative to an axis that passes through the center of mass and is parallel to the axis of interest, M is the total mass of the object, and h is the perpendicular distance between the two axes. Use this theorem and information to determine the moment of inertia (kg·m2) of a solid cylinder of mass M = 5.40 kg and radius R = 8.10 m relative to an axis that lies on the surface of the cylinder and is perpendicular to the circular ends.

Answer 1

As you have said (I question "solid cylinder of mass M = 5.40 kg and radius R = 8.10 m" must be made of lighter than air material or is it a thin disk?)

I = Icm + mh2

Icm= (1/2)mR^2

mh^2=mR^2

I= mR^2(1/2 + 1)
I=(3/2)mR^2
I=(1.5) 5.40 x (8.10)^2= 531 kg m^2