How do I figure out how many moles of hydrochloric acid I have from 38.6 ml of it?

Answer 1

Look up the molar mass of HCl; that will be grams/mole. Look up the density of HCl; that will be grams/ml. Multiply that by the volume to get the no of grams, and divide that by the molar mass to get the number of moles.

molar mass = 36.46 g/mole
density = 0.00148 g/ml

38.6 ml = 0.0570 g

moles = 0.0571 / 36.46 = 0.00156 mole or 1.56millimole

Answer 2

Number Of Moles In Hcl

Answer 3

For the best answers, search on this site https://shorturl.im/axzJJ

This is a simple acid-base problem. The key to solving it is to realize that one mole of H+ (acid) neutralizes one mole of OH- (base). You have to determine how many moles of OH- (from NaOH) you have that need to be neutralized, and that will equal the moles of H+ that you need to add. Recall that molarity, M = mol/L. So you can use this equation to solve for moles, if you are given molarity and volume. Don't forget to convert given values to correct units. For example: How many moles of OH- in 50mL of 0.500M NaOH? First find moles of NaOH: 50mL*(1L/1000mL) = 0.050L M = mol/L rearranges to mol = M*L mol NaOH = (0.500M)*(0.050L) = 0.025mol NaOH Now, how many moles of OH- in one mole of NaOH? One.** Therefore, 0.025mol NaOH*(1 mol OH-/1mol NaOH) = 0.025mol OH- Since one mole of H+ is needed to neutralize one mole of OH-, you would need 0.025mol H+ here. How many moles of HCl will give you 0.025mol H+? Again, one. So you need 0.025mol HCl. Now you have to figure out how many L of HCl solution you will need. Let's say that you have HCl with a molarity of 0.200M. Again, use M = mol/L to calculate L of HCl needed. EDIT: To the first commenter, you should avoid giving the exact answer to the problem given, otherwise people will use Yahoo Answers as a homework cheat source. Not good. ** if you had Ca(OH)2 instead of NaOH, you would have TWO moles of OH- for every one mole of Ca(OH)2, so be aware of the need for this step in the calculation.

Answer 4

moles = Molarity of acid x volume of acid used (in Liters). Whatever your molarity was, multply it by 0.0386 L to find moles of acid.