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Okay so here's how it's going down:
I need to know how to split a single pentagon into five congruent parts in three different ways.
I also need to know how to split a hexagon into six congruent parts in three different ways.
I'm screwed if I don't find out soon so....
Thanks so much all you mathies!!! I really respect you!

2007-11-18 18:40:59 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

This is my homework and I don't know how to do it. It's due tomorrow and I am really confused. I can't think of anything. Only people who will seriously help me with this problem should answer this question. I'm not asking anyone to cheat for me or anything like that. I do not understand what I need to do. People who truly know what they are talking about and can explain it to me are the only ones who should be answering this question

2007-11-18 18:43:47 · update #1

3 answers

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\_/ say thats your hexagon, at each of the corners draw a line from one to the adjacent one
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/ / \
\/_/ bad drawin but you should get my point with the second one do it a line from the EXACT middle to the adjacent side again i cant remember the 3rd one with the pentagon i can only remember one
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I_I again bad drawing but draw a line from th top point to the centre of the bottom line sorry but they are the only ways i can remember

2007-11-18 18:50:54 · answer #1 · answered by Sebastian L 2 · 1 0

1) One way to split a regular n-gon into n congruent parts is to mark the center point and from there draw n line segments to each of the n vertices. Now you have n congruent isosceles triangles.

2) Another way to split a regular n-gon into n congruent parts is to mark the center point and from there draw n line segments to the midpoints of each of the n sides. Now you have n congruent kite shaped figures.

3) A third way to split a regular n-gon into n congruent parts is to mark the center point and from there draw n line segments to a point on each side, which, if you go clockwise around the n-gon, is 1/4 the distance from each vertex to the next one. This will give you n-congruent figures. They won't be symmetric figures like in 1) and 2) but they will be congruent to each other.

2007-11-19 03:09:48 · answer #2 · answered by Northstar 7 · 1 0

You can actually bisect or divide every side of the polygon. You can draw a line bisector and these lines will meet in the center of the polygon. With that, the polygon will be divided into equal parts.

2007-11-19 02:44:56 · answer #3 · answered by rnygelle87 2 · 2 0

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