thanks if you can help.
(3) superscript -2x = ( 1/5) timesx (27) superscript x
the 3 is in parenthesis the negative 2 x is superscript =equals= one fifth in parenthesis times 27 in parenthesis with x as a subscript.
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2007-11-18 16:31:39 · 4 answers · asked by Boo Radley 4 in Science & Mathematics ➔ Mathematics
3^(-2x)=1/5*(27)^x
I hope this is correct.
(1/9) ^x = 1/5 * 27^x
(27*9)^x = 5
243^x=5
x=log_(243)5
2007-11-18 16:40:02 · answer #1 · answered by ? 6 · 0⤊ 0⤋
3^(--2x) = (1/5)(27)^x
=> 5(3^x)^(--2) = (3^x)^3
=> 5 = (3^x)^5
=> 3^x = 5^(1/5)
whencwe xlog3 = 1/5 log5
=> x = (1/5)[(log5)/(log3)]
2007-11-18 16:56:32 · answer #2 · answered by sv 7 · 0⤊ 0⤋
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2016-10-17 05:55:58 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(3)^(-2x) = (1/5)(27)^x
(3)^(-2x) = (1/5)(3)^(3x)
(3)^(5x) = 5
5xln(3) = ln(5)
x = ln(5)/ln(243)
x ≈ 0.2929947 ≈ 0.2930
2007-11-18 16:57:43 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋