If one assumes the volumes are additive, what is the [Cl-] in a solution obtained by mixing 225 mL of 0.625 M KCl and 615 mL of 0.385 M MgCl2?
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i got 1.713 is it right???
2007-11-18 11:27:39 · 3 answers · asked by coca 1 in Science & Mathematics ➔ Chemistry
thank you ....
2007-11-18 11:51:10 · update #1
yes
2007-11-18 11:35:17 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You nade an error somewhere.
Liters x Molarity = moles
0.225 x 0.625 = 0.1406 moles KCl
0.615 x 0.385 = 0.2368 moles MgCl2
moles of Cl^-1 = 0.1406 +2 x 0.2368 = 0.6142 moles Cl^-1
total volume = 0.840 L
Molarity = 0.6142 / 0.840 = 0.731 molar
2007-11-18 19:35:43 · answer #2 · answered by skipper 7 · 0⤊ 0⤋
I answered an almost identical question a day or two ago.
Some people do the arithmetic when answering QQ. I don't - life's too short.
2007-11-19 05:58:39 · answer #3 · answered by Facts Matter 7 · 0⤊ 0⤋