solve each system by elimination
2007-11-18 11:14:22 · 4 answers · asked by sue m 2 in Science & Mathematics ➔ Mathematics
3x-4y= -12
(2x+y= -8)4
3x-4y=-12
8x+4y= -32
11x= -44
x=-4
plug x into one of the problems
2(-4)+y=-8
-8+y=-8
y=0
(-4,0)
=]
2007-11-18 11:26:02 · answer #1 · answered by Anonymous · 1⤊ 0⤋
you can solve it by multipling the second equation by 4 to eliminate the y variable
then you add the two equations:
3x-4y=-12
+ 8x+4y=-32
the y variable is eliminated because -4y+4y=0
so, you have 11x=-44
divide by 11 to get x=-4
plug in -4 for x in one of the original equations:
3(-4)-4y=-12
-12-4y=-12
-4y=0
y=0
2007-11-18 19:26:52 · answer #2 · answered by Valerie 1 · 0⤊ 0⤋
3x - 4y = - 12
8x + 4y = - 32---------ADD
11x = - 44
x = - 4
- 8 + y = - 8
y = 0
x = - 4 , y = 0
2007-11-22 14:29:21 · answer #3 · answered by Como 7 · 1⤊ 1⤋
x= -11
y= -8
2007-11-18 19:23:36 · answer #4 · answered by sydney h 1 · 0⤊ 1⤋