The ionization constant Kw of water at 60 degreees is 1.0 * 10^-13. What is the pH of pure water at this temp?

Question

1. 6.5
2. 7.5
3. 5.5

Answer 1

Definitions:

Kw = [H+][OH-]

pH = - log [H+]

And for neutral water [H+] = [OH-].

Hint: at 25 degrees, Kw = 1.0^10-14