Factor completely: x3 – 26x2 + 48x?

Question

Factor completely: x2 – 6wy + 3xy – 2wx
Factor completely: x2 – 5x – 14
Factor completely: 4x2 – 36y2
Factor completely: 3x2 – 2x – 8
Facor completely: 24x2 + 10x – 4

Answer 1

You can can first factor x out of the equation:

x^3 - 26 x^2 + 48x = x (x^2 - 26x
+48)

Then you can use the quatratic formula.

For the other equations basically you want to find what is common among each of the variables and then factor that out.

Answer 2

x3 – 26x2 + 48x
= x(x^2-26x+48)
= x(x-24)(x-2)

x2 – 6wy + 3xy – 2wx
= x(x+3y)-2w(x+3y)
= (x-2w)(x+3y)

Answer 3

you shouldn't ask people to do your homework for you.
I'll tell you how to do the first one only, though

you first factor out 1 x so you get
x^2-26x+48
then you use the quadratic formula...which is for ax^2+bx+c.....(-b+or- the square root of (b^2-4ac)) all over 2a
anyways, once you do all of that work...you get x=2,24 you then must make them equal to zero...so you get (x-2)(x-24)=0...now dont forget the x you took out earlier so...x(x-2)(x-24) is the complete factor.

your turn :D!

Answer 4

x(x^2 - 26x + 48) = x(x-24)(x-2)
x^2 + 3xy - 6wy - 2wx = x(x+3y) - 2w(3y+x) = (x-2w)(x+3y)
(x-7)(x+2)
(2x-6y)(2x+6y)
(3x+4)(x-2)
2(12x^2+5x-2) = 2(3x+2)(4x-1)