How can i find the value of K?

Question

k^2+2k-3

do i plug in -3 or 0 since they dont give me a binomial?

Answer 1

If you are familiar with factoring
k^2 + 2k - 3 = 0 product = -3 sum = 2,

(-1)(3) = -3 and 3 +(-1) = 2

k^2 - 1k + 3k -3 = 0

k(k-1) 3(k-1) terms inside brackets must equal

(k+3)(k-1)

k+3=0 or k-1=0 these are the roots

k=-3 or k=1 sub one of these found root values back

in to original equation to check that it satifies.

Answer 2

assuming that you are solving k^2+2k-3=0
then you factor the eq into (k+3)(k-1)=0
so k+3 = 0, k=-3 or k-1 = 0, k=1

Answer 3

you need to factor this one out...

k^2+2k-3
the only 2 number that multiply together to get 3 are 3*1...so this one is easier...

just figure out which one is postive and wich one is negative in...
(k?3)(k?1)
since the 2 is positive and the 3 is negative in your starting equation...we know that the large number has to be positive and the other has to be negative
so...
(k+3)(k-1)

therefore...k= -3 or 1

Answer 4

(k+3)(k-1)

then set it equal to 0

(k+3)(k-1) = 0

set each of the () equal to 0

k+3 = 0 and k - 1 = 0
k = -3 adn k = 1