A gas decomposes into 4 separate gases You dont know the pressure Does it change if everything else is unchang

Answer 1

"iu ryu" does not know what they are talking about because R is a constant, always is constant no matter what happens to V, P, or T.

The pressure WILL change!! You can prove this assuming you can use PV = nRT.

Say ABCD is the initial gas and there is 1 mole of it. When it decomposes the equation is ABCD ==> A + B + C + D. Now, if there was 1 mole of ABCD, there is now 1 mole of A, 1 mole of B, 1 mole of C and 1 mole of D because of the 1:1:1:1: relationship. So now there are 4 moles of gas!

Arrange the above PV = nRT to solve for P:

P = nRT / V which is the same thing as P = n * RT/V

If V and T does not change and R is always a constant you can replace RT/V with 'c' for constant. So it becomes

P = n * c

And if n goes from 1 to 4 after the decomposition, P must also increase by 4 times to make both sides equal:

Before P = 1 * c

After P = 4 * c

So pressure after is 4 times greater. Hope this helps.

Answer 2

PV =nRT

If one changes it will balance out. Pressure or volume may increase as R increases.

Answer 3

PV = nRT

R is a constant of nature (ignore anyone who says it can change)

What does n mean, is it changing, and what difference will that make?

Answer 4

If Volume is constant and temperature is constant then pressure
MUST stay the same!