2log4x=5log4(7)?

Question

solve the equation
the 4's are little and a bit below. sry i dont kno how to say it.

Answer 1

In solution "log" is taken as log to base 4:-
2 log x = 5 log 7
log x² = log 7^5
x² = 7^5
x = 7 ^ (5/2)
x = 130 (to nearest whole number)

Answer 2

2 log4(x) = 5log(4)7

If I'm reading your problem correctly above, you have two expressions to the same log base (4).

Don't forget that 2log4(x) is the same as log4(x^2)
and 5log4(7) is the same as log4(7^5)

so now you can equate these 2 expressions, dropping the logs (i.e. take the anti-logs) and you get

x² = 7^5

x = sqrt(7^5) or
approximately 129.6