Solving for angles using Sine, Cosine, and Tangent?

Question

The directions are:

For the following, solve for the angle such that the angle is greater than 0 but less than 360 degrees.

1. sin of the angle= negative 1/2

Could someone please show me how to do this, with steps included

I have been struggling for a long time, like all day on this

I have just asked it 2 times in the math section, once in the polls section, once in the homework help section, and once in the homework help section

Answer 1

learn that
sin 0 deg = 0
30 deg = 1/2
45 deg = sqrt(2)/2
60 deg = sqrt(3)/2
90 deg = 1

then learn that sin is positive in quad 1 and 2

so sin of an angle = -1/2 is when it is in quad 3 or 4

30 + 180 = 210 or 360-30 = 330

Answer 2

Given: sin(30) = 1/2
Therefore, sin(-30) = -1/2
Sin(-30) = sin(360-30) or
Sin(-30) = sin(330) = -1/2

Answer 3

sin(x) = -1/2

To solve, you must take the inverse sine of both sides:
sin^-1(sin(x)) = sin^-1(-1/2)
x = -30
However, since this is not in the domain, you must add 360 degrees to get 330 degrees