Solving for angles using Sine, Cosine, and Tangent?

Question

The directions are:

For the following, solve for the angle such that the angle is greater than 0 but less than 360 degrees.

1. sin of the angle= negative 1/2

Could someone please show me how to do this, with steps included

I have been struggling for a long time, like all day on this

I have just asked it 2 times in the math section, once in the polls section, once in the homework help section, and once in the homework help section

Answer 1

sin θ = - 1/2
θ is in quadrantrants 3 and 4 (due to - ve sign)
sin^(-1) (-1/2) = 30°
θ = 210° , θ = 330°

Answer 2

The sine of an angle is equal to the opposite over the hypotenuse.

In problem 1 the opposite is -1 and the hypotenuse is 2.
angle = arcsin(-1/2) = -30

To convert negative values to a 360 degree circle: just add 360 to the above answer (-30) until you get a number between 0 and 360.
-30 + 360 = 330

Answer = 330

Answer 3

shall we are saying the attitude is 'a' sin a = -a million/2(5d2af075a84322e0ef52ca1832cdd7d5d2af075a84322e0ef52ca1832cdd7d5d2af075a84322e0ef52ca1832cdd7d) sin values are cyclic. while a=0 sin a = 0 while a=30, sin a = 5d2af075a84322e0ef52ca1832cdd7d5d2af075a84322e0ef52ca1832cdd7d5d2af075a84322e0ef52ca1832cdd7d while a=40 5, sin a = 5d2af075a84322e0ef52ca1832cdd7d5d2af075a84322e0ef52ca1832cdd7d(sq. root of -a million/2) while a=60, sin a = (sq. root of three) -a million/2 -a million/2 while a=ninety, sin a = -a million/2 those values are fairly sensible in fixing attitude correct problems and each physique would desire to bear in concepts those values now, sin a = -a million/2(5d2af075a84322e0ef52ca1832cdd7d5d2af075a84322e0ef52ca1832cdd7d5d2af075a84322e0ef52ca1832cdd7d) consequently a = sin ^(5d2af075a84322e0ef52ca1832cdd7d5d2af075a84322e0ef52ca1832cdd7d) [5d2af075a84322e0ef52ca1832cdd7d5d2af075a84322e0ef52ca1832cdd7d5d2af075a84322e0ef52ca1832cdd7d5d2af075a84322e0ef52ca1832cdd7d] and now, fee of sin is advantageous in the 1st and 2nd quadrants. so, the fee of a would be 30 + 5d2af075a84322e0ef52ca1832cdd7d80 (that's in third quadrant) so the respond is 5d2af075a84322e0ef52ca1832cdd7d5d2af075a84322e0ef52ca1832cdd7d0. you could actual bear in concepts that's advantageous wherein quadrant by utilising here rationalization The 4 quadrants, counterclockwise like a capital C, are I, II, III, and IV. In quadrant I, All trig purposes are postiive; in quadrant II, Sine and its reciprocal are advantageous; in quadrant III, Tangent and its reciprocal are advantageous; in quadrant IV, Cosine and its reciprocal are advantageous. Mnemonics for All, Sine, Tangent, Cosine: All Silver Tea Cups.

Answer 4

Let's imagine the perspective is 'a' sin a = -(half of) sin values are cyclic. When a=zero sin a = zero when a=30, sin a = half of when a=45, sin a = 1/(rectangular root of two) when a=60, sin a = (rectangular root of 3) / 2 when a=90, sin a = 1 these values are beautiful valuable in fixing perspective associated issues and each person must keep in mind these values now, sin a = -(half) consequently a = sin ^(-1) [-1/2] and now, value of sin is optimistic within the first and second quadrants. So, the value of a can be 30 + one hundred eighty (which is in third quadrant) so the reply is 210. You could comfortably don't forget which is constructive wherein quadrant with the aid of the next explanation The 4 quadrants, counterclockwise like a capital C, are I, II, III, and IV. In quadrant I, All trig capabilities are postiive; in quadrant II, Sine and its reciprocal are optimistic; in quadrant III, Tangent and its reciprocal are optimistic; in quadrant IV, Cosine and its reciprocal are constructive. Mnemonics for All, Sine, Tangent, Cosine: All Silver Tea Cups.

Answer 5

you need to know the 4 quadrant rule. referring to the 4 quadrants in anticlockwise order, quadrant 1, all are positive, q2 sine is positive, q3 tan is positive and q4 cos is positive ( there is a rhyme All Stations To City, ,to help to remember. So sign is negative in Q3 and Q4, that is 180 to 360 degrees. from an equilateral triangle split into 2, sin 30 = 1/2 ( q1), so for sin(angle) = -1/2, angles are 180+30 = 210 and 360 - 30 = 330. Sometimes people work +/- 180, in which case your angles would be -30 and -150. As always with angles a sketch helps.

Answer 6

Use the graphing calculator to do this (always make sure that the mode is in degrees):

sin of the angle = negative 1/2
sin of the angle = -30 degrees

press 2nd sin.
then, press negative 1/2.
press enter.

this doesn't even make sense. i did the following steps, and the angle is less than 0!!! (STUPID ME!!!... Oh did I do it incorrectly?) It says,"For the following, solve for the angle such that the angle is greater than 0 but less than 360 degrees."

Answer 7

let the angle be A;
sinA=-1/2=-sin30=sin210or sin 330
A=210or 330 degrees

Answer 8

well.. sin (100) is about -1/2 ... i can't explain you why.. may be someone else..