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1. The height of this oversized container is 3 m. Its diameter is
2 m.

what is the area?

(a) 16 m2 <
(b) 9.42 m3 <<
(c 18 m2<<< 2 is supposed to be small

(d) 18.84 m2<<<2 is supposed to be small


2. What is the area of an isosceles trapezoid with bases of 17.5 cm and 12 cm respectively and a height of 10 cm?

(a) 147 cm3<<<3 is supposed to be small

(b) 147 cm2<<<<2 is supposed to be small

(c) 147.5 cm2<<<2 is supposed to be small

(d) 147.5 cm


3. Re-write the equation 4x - 2 = y-intercept format:

(a) y = 4x + 2

(b) y = - 4x +2

(c) y = 4x - 2

(d) y = -4x - 2


4. In the equation y = 2x + 1, which of these is a point on the graph?

(a) 0,2

(b) 1,4

(c) 2,6

(d) 1,3


5. In the equation 2x - y = 5, the slope is

(a) 2

(b) -2

(c) 5

(d) - 5



6. In the equation 2x - 5 = y, the y-intercept is

(a) 2

(b) -2

(c) 5

(d) - 5

2007-11-18 09:27:54 · 2 answers · asked by Anonymous in Education & Reference Homework Help

2 answers

1. The area of the cylinder (not including the ends) is h*pi*d = 6pi = 18.84 m2

2. Area = ave of the bases * ht = 10 * (17.5 + 12)/2 = 5(29.5) = 147.5 cm2

3. c. You just moved things to the other side of the = sign.

4. d. You get this by substituting the x,y points into the equation and seeing if it's true.

5. y = mx + b; the slope is m
2x - y = 5
2x - 5 = y
slope = 2

6. y = mx + b; the slope is b
so the answer is d, -5

2007-11-18 09:39:03 · answer #1 · answered by Steve A 7 · 0 0

3 = b
5 = b
6 = c

i wish i could help you... i am in alg2/trig now... but i am glad that i can help you... i can only hope it didn't come too late.

2007-11-18 17:38:17 · answer #2 · answered by Anonymous · 0 1

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