how do i factorise these:
1 - 4x+8
2 - m^2-n^2
2 - xy-x
ETC. how will i work them out with squares and fractions like: x^2/2 - x^3/4
2007-11-18 09:17:01 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
take out common factors first
4x+8=0
4(x+2)=0
m^2-n^2=0
(m-n)^2=0
xy-x=0
x(y-1)=0
thats about all i can do because u have two variables
2007-11-18 09:19:16 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1. 3(-x+2)
2. (m-n) (m+n)
3. x(y-1)
2007-11-18 09:20:14 · answer #2 · answered by Anonymous · 0⤊ 0⤋
1 - 4x+8 = -4(x-2)
2 - m^2-n^2 = -(m-n)(m+n)
3 - xy-x = -x( y+1)
x^2/2 - x^3/4 = (x^/2)(1- x/2)
2007-11-18 09:20:42 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
4x + 8 turns into (2x)*(2x) + (2)*(2)*(2)
m squared - n squared turns into [(m)- (n)] *[(m)-(n)], this one is just your F.O.I.L. method turned bckwards (mulitiply the first, outside, inside, last factors together)
xy-z would be [(x)-z] * [(y-z)]
2007-11-18 09:23:52 · answer #4 · answered by Anonymous · 0⤊ 0⤋
4(x+2)
(m-n)(m+n)
x(y-1)
x^2 / 2 = -2x^2 i think
2007-11-18 09:22:52 · answer #5 · answered by AP12 2 · 0⤊ 0⤋
4(x+2)
(m-n)^2
x(y-1)
2007-11-18 09:20:02 · answer #6 · answered by Anonymous · 0⤊ 0⤋
AAAAHHHHHHHH evil math question of doooooooommmm!!!!!!!! sorry i hav no clue
2007-11-18 09:20:12 · answer #7 · answered by hollistersocallove13 2 · 0⤊ 1⤋