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Using the Gibbs-Helmholtz equation (T = H / S), why do all compounds decompose into their individual elements if heated to high enough temperatures?

2007-11-18 03:20:16 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

From how I understood this equation, compounds decompose at high temperatures simply because their entropy values would be low. If we were supposed to solve for S, then we'd have to divide both sides of the equation by T. Then we end up with: "S = H/T). This means that the higher the temperature, the lower the entropy. Since forward reactions favor higher entropy values than lower entropy values, the reverse reaction will happen and you get your decompostion.

2007-11-18 03:45:59 · answer #1 · answered by Great_Magician13 2 · 0 0

Because the bonds between compounds break when heated. When heated it provides sufficient energy to break the bonds decomposing them into elements..

2007-11-18 11:43:36 · answer #2 · answered by Sharoof 2 · 0 0

YES!!!!.

In fact they will breakdown further into protons, electrons neutrons, and further again. But this is nuclear physics.!!!! But we are talking temperatures in 10,000 degrees C or even higher into millions of degrees C.

2007-11-18 11:29:43 · answer #3 · answered by lenpol7 7 · 0 0

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