2007-11-18 03:04:48 · 4 answers · asked by jess r 1 in Science & Mathematics ➔ Chemistry
In your previous question, the mass of Al was calculated to produce 12 moles of Al2O3. In this case, The mass of Al to react with 75 grams of O2 is asked. Remember the equation:
4 Al(s) +3 O2(g) ---------> 2 Al2O3(s)
Molar masses:
Al = 27 g/mol
O2 = 2x16 = 32 g /mol
According to the equation, 4 moles Al (4x27= 108 g) reacts with 3 moles O2 (3x32 = 96 g), then the mass of Al to react with 75 g O2 Will be:
75 x 108 / 96 = 84.375 g Al
2007-11-18 03:47:38 · answer #1 · answered by Guray T 6 · 0⤊ 0⤋
Geez that is simple plus a trick question. You never use aluminum in this circumstance.
2007-11-18 11:07:08 · answer #2 · answered by Tom _ Red Sox fan 3 · 0⤊ 0⤋
4Al(s) + 3O2(g) = 2Al2O3(s)
Moles(O2) = 75/32 = 2.34 (Approx) equivalent to 3
Moles(Al) = 2.34 x 4/3 = 3.125
Mass (Al) = 3.125 x 27 = 84.375g.
2007-11-18 11:26:27 · answer #3 · answered by lenpol7 7 · 0⤊ 0⤋
52 gms. is PERFECT !!!
2007-11-18 11:11:38 · answer #4 · answered by conradticker 1 · 0⤊ 0⤋