English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

......positive terms. If (the summation from n=1 to infinity) of a_n is convergent, then (the summation from n=1 to infinity) of [sqrt(a_n)/n] is convergent.

Thanks!

2007-11-17 21:40:10 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

Use the Comparison Test: show that sqrt(a_n)/n < a_n.

2007-11-18 03:13:51 · answer #1 · answered by Tony 7 · 0 0

I would think the answer is true but I don't know how to prove it, sorry :(

2007-11-17 22:03:33 · answer #2 · answered by Anonymous · 0 0

fedest.com, questions and answers