How do you solve for e in the given equation:n=N/(1+Ne²)?

3 ⤊

2007-11-17 20:55:17 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

n (1 + N e ²) = N
1 + N e ² = N / n
N e ² = N/n - 1
e ² = (N/n - 1) / N
e ² = (1/N) (N - n) (1 / n)
e ² = (N - n) / (N n)
e = √ [ (N - n) / (N n) ]

2007-11-22 05:44:24 · answer #1 · answered by Como 7 · 3⤊ 1⤋

n =N/(1+Ne^2)

1 + Ne^2 = N/n
Ne^2 = N/n -1

e = sqrt( [N/n -1] / N)

2007-11-18 05:00:26 · answer #2 · answered by Anonymous · 0⤊ 1⤋

e=square root of [(N^2/n) - N]

2007-11-18 05:00:06 · answer #3 · answered by pawpawpaw 3 · 0⤊ 1⤋