consider the points A(0,2), B(-6,4) and the line L1 with equation 3y-x-12=0?

Question

consider the points A(0,2), B(-6,4) and the line L1 with equation 3y-x-12=0.
1) Find the equation of the circle C whose center is the point of intersection of the line L1,and the segment AB, and whose diameter is equal to the length of the segment AB

Answer 1

I've considered the points, but I still can't do the rest of your homework ! ! !

Answer 2

AB:
y = - (2/6)x + 2
x + 3y = 6
x - 3y = - 12
2x = - 6
x = - 3
y = 3
C = (- 3, 3)
r^2 = 9 + 1 = 10
1)
(x + 3)^2 + (y - 3)^2 = 10