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how do i get rid of this logarithm:

0.5 = log (a/b)

2007-11-17 19:26:32 · 2 answers · asked by jabrahams71 1 in Education & Reference Higher Education (University +)

2 answers

If the log is base 10, then

10^0.5 = a/b

also written √10 = a/b

2007-11-17 19:35:07 · answer #1 · answered by gp4rts 7 · 0 0

the final definition of a log is this: log[base b](a) = c is comparable to asserting a = b^c So as a result, you have log[base 3](X/2) = 2, meaning x/2 = 3^2. you are able to resolve it from right here. that is actual which you're able to desire to try this as a substitute: 3^[ log[base 3] (X/2) ] = 3^2 (x/2) = 3^2 yet you ended up multiplying by way of three on the left as a substitute of taking 3 to the potential of what grew to become into on the left.

2016-12-09 00:54:41 · answer #2 · answered by ? 4 · 0 0

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