The number in front of the square root are like terms:
2 + 5 = 7
since youre just adding the square root, you just leave the √11 alone :
7√11
2007-11-17 14:38:15
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answer #1
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answered by Anonymous
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Adding/subtracting radicals is similar to adding/subtracting polynomials.
When adding/subtracting polynomials, you can only combine "like" terms, that is, terms that have the same combination of variables and exponents.
i.e. you can add 3x + 5x to get 8x, but you can't combine the terms 3x + 5y, or 3x + 5x^2
When adding/subtracting radicals, you can only combine "like" radicals, that is, terms that have the same "Radicand" which is the number/expression inside the radical symbol.
i.e. you can add 3√x + 5√x to get 8√x, but you can't combine the terms 3√x + 5√y, or 3√7 + 5√6
in your case, since both terms have radicand of 11, you may combine them so 2√11 + 5√11 = 7√11
2007-11-17 14:48:10
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answer #2
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answered by golfingcanuck2001 2
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authentic dat! the respond is d my guy. in case you do not have faith flow purchase a ti89, positioned it in suitable mode and notice what it provide you with. yet of direction it extremely is for lazy human beings like me. yet extremely all you have is a pair of radical 11's elevated by applying some coefficients, upload the coefficents jointly and do not forget approximately the ten!
2016-10-17 03:33:27
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answer #3
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answered by bolen 4
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treat the square root like a variable.
7sqrt11
2007-11-17 14:34:09
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answer #4
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answered by peachzncream3127 2
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Two square roots of eleven plus five square roots of eleven equals seven square roots of eleven.
2007-11-17 14:37:13
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answer #5
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answered by Tim C 7
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oh wow.... ha ha funny stuff... and the answers is 7 square root 11.....
2007-11-17 14:37:57
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answer #6
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answered by Anonymous
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7x(sqrt11)
2007-11-17 14:38:30
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answer #7
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answered by Anonymous
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