English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Not sure how to do this...any help would be appreciated.

1.) A rectangle is inscribed in a semicircle of radius 2. What is the largest area of the rectangle?

2007-11-17 13:40:43 · 4 answers · asked by Sean G 1 in Science & Mathematics Mathematics

4 answers

Shetch the semi circle with rectangle contained therein.
Draw radius r = 2 such that r makes angle θ
with horizontal at centre of circle.
Horizontal component of r = 2 cos θ so base of rectangle = 4 cos θ
Vertical component of r = r sin θ = 2 sin θ
Area of rectangle = 4 (cos θ) (2 sin θ)
A = 8 sin θ cos θ
A = 4 (2 sin θ cos θ)
A= 4 sin 2θ
A max = 4 units ²

2007-11-21 10:04:58 · answer #1 · answered by Como 7 · 1 1

You should note that the area of the rectangle is 2xy where (x,y) is a point on the circle, making it easy to write y in terms of x. Then do your max/min procedures. The value for "x" is close to 1.2 and "y" is close 1.6, but these are the correct values.

2007-11-17 14:22:26 · answer #2 · answered by ted s 7 · 0 0

the area is the square root of 15

2016-05-24 01:00:27 · answer #3 · answered by nakita 3 · 0 0

You just measer the long side on the bottom and the short side going up and you times those two numbers
P.S. that is so easy!!!!!

2007-11-17 13:44:48 · answer #4 · answered by Anonymous · 0 1

fedest.com, questions and answers