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ok guys, we did a calorimetry kind of thing lab and we're supposed to measure the heat of neutralization.

In this equation:
NaOH + HCl ---> NaCl + H2O

first we have to find moles of water right? cuz the heat of neut is kj/mol of water formed.

What i have is: 50 mL of 2 M NaOH, and 40 mL of 2 M HCl.
ok so my question is, how do i calculate the number of moles of water??? is it the same as that of HCl?? plz any clarifications would be greatly appreciated!!

2007-11-17 12:52:50 · 2 answers · asked by Curious 1 in Science & Mathematics Chemistry

2 answers

it should be the same because the mole to mole ratio in the equation is the same

2007-11-17 13:44:10 · answer #1 · answered by Help?? 2 · 0 0

In this equation:
NaOH + HCl ---> NaCl + H2O
Once you get rid of spectators, the equation becomes:
OH- + H+ ==> H2O
50 mL of 2 M NaOH is 0.1 mole NaOH (calculated by 0.050L * 2M), and 40 mL of 2 M HCl is 0.08 mole HCl.
You have more NaOH than HCl. That is to say, HCl or simply H+ is the limiting reactant. Hence at most you may form 0.08 mole of H2O according to the reaction equation.----You are right---in this case it is the same as the moles of HCl.

2007-11-20 01:23:32 · answer #2 · answered by Hahaha 7 · 0 0

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