x^2+10x+24
2007-11-17 12:11:22 · 9 answers · asked by Chrisso 2 in Science & Mathematics ➔ Mathematics
the problem says to factor completely over the set intergers
2007-11-17 12:12:27 · update #1
To factor this, we are looking for two numbers whose sum adds up to to 10 and whose factor adds up to 24. In this case, we can factor x^2+10x+24 to (x+6)(x+4), 6+4=10 and 6x4=24
If we solve for x, we get x=-6 and -4
2007-11-17 12:15:41 · answer #1 · answered by Himitsu 3 · 0⤊ 0⤋
x^2 + 10x + 24
=>x^2 + 6x + 4x + 24
=>x(x + 6) + 4(x + 6)
=>(x + 6)(x + 4)
2007-11-17 20:17:27 · answer #2 · answered by mohanrao d 7 · 0⤊ 0⤋
= x^2 + 10x + 24
= (x + 4)(x + 6)
Answer: x = - 4, - 6
2007-11-17 21:55:38 · answer #3 · answered by Jun Agruda 7 · 2⤊ 0⤋
x²+10x+24 = (x+6)(x+4)
2007-11-17 20:15:28 · answer #4 · answered by DWRead 7 · 0⤊ 1⤋
(x+4)(x+6)
find 2 factors of 24 that multiplied = 24 and added = 10
2007-11-17 20:25:48 · answer #5 · answered by Anonymous · 0⤊ 0⤋
(x+4)(x+6)
2007-11-17 20:17:12 · answer #6 · answered by UNIQUE 3 · 0⤊ 0⤋
24 = 1x24, 2x12,3x8, 4x6
only 4+6 = 10
(x+6)(x+4)
2007-11-17 20:14:46 · answer #7 · answered by norman 7 · 0⤊ 0⤋
(x+4)(x+6)
2007-11-17 20:16:05 · answer #8 · answered by someone else 7 · 0⤊ 1⤋
(x+6)(x+4)
2007-11-17 20:14:37 · answer #9 · answered by jenn. 2 · 0⤊ 1⤋