Parametric equations: x = 2(t)^2 and y = 4t. Find the cartesian equation.?

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I realise it's easy, I'm just checking I'm doing it right.

2007-11-17 10:52:37 · 5 answers · asked by Me 1 in Science & Mathematics ➔ Mathematics

y=4t implies t=y/4. Substitute into first parametric. we get x=2(y/4)^2 we get on rearranging a parabolic equation
y^2=8x

2007-11-17 11:03:03 · answer #1 · answered by mwanahamisi 3 · 0⤊ 0⤋

t = â(x/2)

y = 4â(x/2)

2007-11-17 19:02:28 · answer #2 · answered by MathGuy 6 · 0⤊ 0⤋

Eliminate t
t=y/4
x = 2(y/4)^2
x = y^2/8

2007-11-17 18:57:54 · answer #3 · answered by norman 7 · 0⤊ 0⤋

x = 2(t)^2

2x = t^2

t = + or - sq.rt (2x)

y = 4t

y = 4 * + or - sq.rt(2x)

y = + or - 4*sq.rt. (2x)

2007-11-18 07:42:35 · answer #4 · answered by RATTY 7 · 0⤊ 0⤋