What is the de Broglie wavelength of an electron that strikes the back of the face of a TV screen at 1/10 the speed of light?
_____m
2007-11-17 10:41:02 · 4 answers · asked by w_rayas07 1 in Science & Mathematics ➔ Physics
The de Broglie wavelength
L=(h/mv)sqrt(1- (v/c)^2)
h= Planck's constant (6.63 E − 34 joule-seconds)
m - rest mass of the electron (9.10938188 E-31 kg)
v - velocity of the electron (m/s)
c - the speed of light (2.99 E+8 m/s)
L= (6.63 E − 34 x 10/ (9.10938 E-31 x 2.99 E+8)sqrt(1-(1/10)^2)
L=2.5E-11m
L=250 nm
2007-11-17 10:47:50 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
Its really 2.43E-11
2014-05-05 07:21:55 · answer #2 · answered by Jose 3 · 2⤊ 0⤋
All of these answers come out incorrect on Pearsons masteringphysics question. I don't know what they want me to put as the answer
2015-06-25 22:57:50 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I would strongly suspect that this is nonrelativistic, so you can simply use
wave = h/m(0.1c)
m = 9.11E-331kg
h = 6.63E-34Js
c = spped of light = 3E8
2007-11-17 10:50:02 · answer #4 · answered by Anonymous · 1⤊ 0⤋