A ball of mass M1 = 64.0 kg moves with an initial speed vi = 3.7 m/s into the barrel of a spring gun of mass..

Question

M2 = 153.0 kg, which is initially at rest on a frictionless surface. The spring has a spring constant k = 1640 N/m. What is the maximum compression of the spring?

Answer 1

Ke1=Ke12 + Ps

(1/2)m1V1^2= (1/2)(m1+m2)V2^2 + (1/2)kx^2
m1V1^2= ((m1+m2)V2^2 + kx^2

x= sqrt[(m1V1^2- ((m1+m2)V2^2)/k]

;-)

Answer 2

Say u is the value whilst the spring is compressed to its optimal(it might desire to no longer be the main suitable velocity). the main suitable velocity relies upon on no remember if the ball maintains to be in the gun or no longer. m1v1= m1u+m2u 0.5m1v1^2 = 0.5kx^2 + 0.5m1u^2+0.5m2u^2 u= (m1/(m1+m2))v1 = a million.15142 fifty two*3.a million^2 = 1780x^2 + fifty two*a million.15142^2 + 88*a million.15142^2 x = ((fifty two*3.a million^2 - (fifty two*a million.15142^2 + 88*a million.15142^2))/1780)^0.5 = 0.40 two (m)