Word problem involving equation.?

Question

Two positive numbers are squared their sum is 11810. If the first number is 1 less than 2 times the second number, what is the smaller number.

Answer 1

A^2+B^2=11810
2B-1=A <
Now, substitute (2B-1) for A in the first equation.
(2B-1)^2+B^2=11810
4B^2-2B-2B+1+B^2=11810
5B^2-4B+1=118180
5B^2-4B-11809=0
QUADRATIC FORMULA:
B= (-(-4)(+/-)sqrt((-4)^2-4(5)(-11809))/2(5)
B=(4(+/-)sqrt(16 +236180))/10
B=(4(+/-)486)/10
B=49 or B=-48.2
The numbers are positive, so B must be 49.
2B-1=A :: 2(49)-1=A
A=97
The smaller number is, obviously, 49.

Answer 2

So let x represent the smallest number:
x^2 + (2x+1)^2 = 11810

Answer 3

49 ( the other is 97)

Let the numbers be x and y

x=2y-1

x^2+y^2=11810 = (2y-1)^2 + y^2

5y^2-4y-11809 = 0

y=49 (the other root is negative)

Answer 4

(2x --1)^2 + x^2 = 11810
=> 5x^2 --4x -- 11809 = 0
=> (x --49)(5x + 241) = 0
=> x = 49, --241/5
smaller one is 49 or --241/5

Answer 5

first collect the given data. then check what u have to find. now search for the formulas involving those given data and the data which u have to find. now solve it...

Answer 6

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