A. for "geometric" using multiplication by a factor:
1, 1/4, 1/16, 1/64
divide by 4 each time or multiplying by 1/4 each time
same as dividing 1 by 2^0, 2^2, 2^4, 2^6
same as pattern 1/(1*1), 1/(2*2), 1/(4*4), 1/(8*8)
same as pattern (8*8)/64, (4*4)/64, (2*2)/64, (1*1)/64
B. for "arithmetic" using addition or subtraction by a fixed factor:
64/64, 43/64, 22/64, 1/64
same as
1, 43/64, 11/32, 1/64
subtracting 21/64 each time
For "arithmetic" or "adding/subtracting" a fixed factor each time, you would have to average the difference between the first and fourth term, divide by three steps, and either add to 1/64 until you get to 1 or subtract from 64/64 until you get to 1/64, subtracting or adding the same number each time.
Example: for 10, 7, 4, 1
you would subtract 10-1 to get 9,
divide 9 by 3 steps to get "3" as the factor
So 10 -3 to get 7 -3 to get 4 -3 to get 1
or working backward 1 +3 to get 4 +3 to get 7 +3 to get 10
Here: for 64/64, __ , __ , 1/64
same as figuring out sequence
64, __, __, 1
you get 64-1 to get 63
divide 63 by 3 steps to get "21"
so "21/64" is your factor
that you add or subtract each time:
64/64, 43/64, 22/64, 1/64
same as
1, 43/64, 11/32, 1/64
subtracting 21/64 each time
C. If your teacher means you can use other patterns besides "geometric" or "arithmetic" you can follow any pattern as long as you show how it repeats clearly:
1, 6, 4, 1/64, 2, 7, 5, 2/75
1, 2, 6, 1/(2^6), 2, 3, 7, 2/(3^7)
1, 1/32, 1, 1/64, 1, 1/128, 1, 1/256
1, 1/64, 1, 1/64, 1, 1/64, 1, 1/64
2007-11-17 08:40:59
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answer #1
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answered by Nghiem E 4
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pretend the 1 is really 1/1
so the problem is
1/1, 1/?, 1/?, 1/64
as the one numerator is constant
so in ttwo spteps you need to get from 1 to 64 by the same operation - only powwers of two can do this, so the answer is
for the first one 1/2^2, the second one is 1/(2^2)*(2^2)=16 as you rightly say
well done
2007-11-17 08:32:33
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answer #3
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answered by Dad 6
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