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(Ka1 = 7.2 10-3, Ka2 = 6.3 10-8, and Ka3 = 4.2 10-13).
(a) Which Ka value is most important to this buffer?
b) What is the buffer pH?

2007-11-17 08:21:11 · 1 answers · asked by Ecka 1 in Science & Mathematics Chemistry

1 answers

(a) Ka2 = 6.3x10^-8(M)
(b) pH = -log(Ka2*[NaH2PO4]/[Na2HPO4]
= -log(6.3x10^-8*0.45/0.43)
= 7.18

2007-11-18 15:53:59 · answer #1 · answered by Hahaha 7 · 0 0

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