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Integrate (area integral) x*y dA where R is the region bounded by the graphs of y=(x)^1/2, y=(x/2), x=2 and x=4 would the bounds for x be 2 (lower) to 4 (upper) and the bounds for y be (1/2) (lower) (x)^(1/2) (upper) ?

Area Integral = Double Integral

2007-11-17 08:20:10 · 2 answers · asked by offycakes 1 in Science & Mathematics Mathematics

2 answers

I assume you just made a typo and meant to say (x/2) (lower).

You are right, assuming you are setting up the integral with the dy integral on the inside and dx on the outside.

2007-11-17 08:41:54 · answer #1 · answered by Michael M 7 · 0 0

If dA = dy dx the y limits are [ x /2, sqrt x] and x limits are [2 , 4] You dropped the x when you typed your lower limit for y.

2007-11-17 08:45:12 · answer #2 · answered by ted s 7 · 0 0

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