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Doing Chemistry Need Help
Greatly Appreciated Thanks

2007-11-17 07:41:40 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

You would need to be more specific, but, in general, faster rate means less time needed, in chemistry as in everything else.

2007-11-17 07:46:52 · answer #1 · answered by Facts Matter 7 · 0 2

It depends on what you imply under "time of reaction". Usually, in kinetics people talk about t1/2, which time during which the concentration of the PARTICULAR reagent doubles or drops by factor of 2 (depending on if you use products or reactants to monitor the kinetics of the reaction). For example,
in the reaction A-->2B, the concentration of A will decrease by half slower than the concentration of B will increase by a factor of 2.
There is another complication. Depending on the order of the reaction, the expression for t1/2 will also differ.
For example, the first order reaction,
t1/2=Ln2/k, where k is the rate constant.
for the second order reaction,
t1/2=1/k*1/[Ao], where k - rate constant, and [Ao]-initial concentration of reagent A.
So you have to clearly state how do you define the time of your particluar reaction before answering the question about the relationship between time and rate constant.
Finally, a lot of processes have more than one rate constant:
Reaction A+B-->2C --> D have two rate constants and the expression for the rate of reaction as judged by the concentration of C will be:
dC/dt=k1[A][B]-k2[C]^2. From this equation, the expression for t1/2 will be quite complicated.

2007-11-17 12:37:21 · answer #2 · answered by Anonymous · 0 1

They are inversly proportional.
Rate = x/seconds

2007-11-17 07:47:04 · answer #3 · answered by java2bobby 3 · 0 1

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