4x2-2x-10=0
solve by completing the square.... thank you so much.
2007-11-17 07:17:35 · 3 answers · asked by Smart S 2 in Science & Mathematics ➔ Mathematics
please help. the answer only is okay
2007-11-17 07:25:58 · update #1
pleassssssssssssssssse
2007-11-17 07:32:04 · update #2
4(x² - (1/2)x - 10 / 4) = 0
( x² - (1/2)x + 1/16 ) = 1/16 + 10/4
(x - 1/4)² = 41/16
(x - 1/4) = ±√41 / 4
x = 1/4 ±√41 / 4
x = (1/4) (1 ±√41)
2007-11-21 09:42:59 · answer #1 · answered by Como 7 · 1⤊ 1⤋
Divide by 4, move the constant term to the right side, and then add 1/4,
x^2 - x/2 + 1/4 = 5/2 + 1/4
(x - 1/2)^2 = 11/4
x = 1/2 ±√11 / 2
2007-11-17 07:26:40 · answer #2 · answered by sahsjing 7 · 1⤊ 0⤋
4x^2 - 2x - 10 = 0
x^2 - 0.5x - 2.5 = 0
x^2 - 0.5x +0.0625 - 2.5 = 0.0625
x^2 - 0.5x -2.4375 = 0.0625
x^2 - 0.5x = 2.5
x^2 - 0.5 - 2.5 = 0
(x + 1.851)(x -1.351)
x = 1.851
x = -1.351
2007-11-17 12:54:48 · answer #3 · answered by Eduardo (lalo) Leal 2 · 0⤊ 1⤋